Si a = 2 ; b = 5 ; c = -3 ; d = -1 ; f = 0
Entonces:
i) 5a^2 - 2bc - 3d = 5(2)^2 - 2(5)(-3) - 3(-1) = 53
ii) 4ab - 3bc - 15d = 4(2)(5) - 3(5)(-3) - 15(-1) = 100
iii) 6a^3f = 6(2)^3 . (0) = 0
iv) 2a^2 -b^3 -c^3 - d^5 = 2(2)^2 - (5)^3 - (-3)^3 - (-1)^5 = - 89
v) 3(a-b) + 2(c-d) = 3(2-5) + 2(-3-(-1)) = - 13
vi) c/3 + b/5 - a/2 = (-3)/3 + (5)/5 - 2/2 = -1
vii) (b+c)^2 = (5 - 3)^2 = 4
